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Is the Variable Number of Bananas in a Bunch Continuous or Discrete

  • (6 points) Classify each of the following random variables as discrete or continuous.
    a) The weight of a bunch of bananas.
    Continuous
    b) The number of students in a statistics class.
    Discrete
  • (11 points) Ford Motor Company's total sales revenues for 1986 are shown in the table below. Construct a relative frequency bar chart.
    Region Revenue ($billion)
    U.S. 50
    Canada 10
    Europe 13
    Latin Am. 3
    All Other 2

    Answer:

    Relative Frequencies US	50/78 = 0.64 Can	10/78 = 0.13 Euro	13/78 = 0.17 L.A.	 3/78 = 0.04 Other	 2/78 = 0.03          
  • (7 points) Telephone calls put on hold have mean length 55 seconds and standard deviation 15 seconds. Find the z-score for a call that was put on hold for 82 seconds. If the distribution of holding times is mound-shaped, is an 82 second wait unusual? Why?

    z = (x - )/ = (82-55)/15 = 27/15 = 1.8

    This is 1.8 standard deviations above the mean. This is not unusual. 95% lie within 2 standard deviations.

  • (20 points) The salaries of a sample of 6 CEOs, in millions of dollars are:

    2, 1, 5, 8, 5, 3.

    Compute the following.

    a) mean

    = (2 + 1 + 5 + 8 + 5 + 3)/6 = 24/6 = 4

    b) median

    1, 2, 3, 5, 5, 8 median = (3 + 5)/2 = 4

    c) mode

    5

    d) range

    8 - 1 = 7

    e) first quartile

    i = 25/100 x 6 = 1.5 Round up to 2. Q1 = x2 = 2.

    f) third quartile

    i = 75/100 x 6 = 4.5 Round up to 5. Q3 = x5 = 5.

    g) interquartile range

    5 - 2 = 3

    h) variance

    s2 = [ (2-4)2 + (1-4)2 + (5-4)2 + (8-4)2 + (5-4)2 + (3-4)2 ]/(6-1) = 32/5 = 6.4

    i) standard deviation

  • (10 points) A boxplot is shown below for the number of farms in each state in the U.S. Estimate the values of the Five Number Summary from the boxplot.
                -----------------    ---I       |       I------------                    *       -----------------    +---------+---------+---------+---------+---------+-----           0        35        70       105       140       175

    Minimum: 0
    Q1: 10
    Median: 37
    Q3: 65
    Maximum: 185

  • (9 points) A consultant has presented his client with three alternative research studies methods. If the client chooses alternative A, the consultant will have to hire 1 additional employee. Two employees will have to be hired if the client chooses B, and 5 if the client chooses C. The probability that the client will select alternative A is 0.1, with P(B) = 0.5 and P(C) = 0.4. Find the expected number of employees that will have to be hired.
                X         P(X)                X P(X)                 1         0.10                 0.10                  2         0.50                 1.00                  5         0.40                 2.00                                      E(X) =                        X P(X) =  3.10          
  • (9 points) A certain computer has two power supplies. The computer can operate on either one. On any given day, the first is 99% reliable and the second is 99.5% reliable. What is the probability that on any given day the computer will lose its power?

    P(lose power) = P(first fails and second fails)
    = P(first fails second fails)
    = P(first fails) P(second fails)
    = (0.01) (0.005)
    = 0.00005

  • (9 points) The results of an experiment studying children's understanding of TV commercials are shown in the table.
                Age                                        5-7    8-10      11-13    Don't understand        55     65         30      Understand              45     35         70          
    1. What is the probability that a 9 year old will understand TV commercials?

      P(understanding | 9 years old) = 35/(65 + 35) = 0.35

    2. Is understanding independent of age? Use probabilities to demonstrate your answer.

      P(understanding) = (45+35+70)/300 = 0.50

      P(understanding | 8-10 years old) = 35/(65+35) = 0.35

      These are not equal, so understanding and age are dependent.

  • (15 points) A production line produces bolts. Machine X produces 60% of the bolts and Machine Y produces the remainder. 0.1% of the bolts produced on Machine X are defective and 0.2% of the bolts produced on Machine Y are defective.
    1. Construct a probability tree for this situation.

    2. What is the probability of a bolt being defective?

      P(D) = P(X and D or Y and D) = P(X D) + P(Y D)
      = 0.0006 + 0.0008 = 0.0014

  • dickersonantoomp.blogspot.com

    Source: http://www.ma.iup.edu/~hedonley/ma214/t1s95/

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